Answer:
Let's us assume that we have the following table of Employee.
Emp_Id
| Emp_Name
| Emp_Salary
|
1
| Shiv
| 17000
|
2
| Raju
| 13500
|
3
| Sham
| 15000
|
4
| Moosa
| 11000
|
5
| Feroz
| 12000
|
Now we want to find out second highest salary from Employee table, as you see
that the second highest salary is 15000 and we want to display the same.
Query:-
SELECT Emp_Name,Emp_Salary
FROM Employee e1
WHERE
2 = (SELECT COUNT(DISTINCT (e2.Emp_Salary))FROM Employee e2 WHERE e2.Emp_Salary >= e1.Emp_Salary)
The above employee table contains two same records as second highest salary so
the result set will look like below output table.
Output:-
| Emp_Name | Emp_Salary |
| Sham | 15000 |
If the table contains two or more same record of salary which is the second
highest salary then the query will give you all the record of second highest
salary as you see in the above output table.
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